Exploring 5 2 Part 2 Notes Solving Polynomial Equations Algebraically

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  • What's up good people this is Mr Bergman here at section
  • Okay okay now you can do the rest of these if you like so we've got y = 4 x 4th + 7 x^
  • Intro ...
  • This
  • ... of of foiling It just organizes the terms differently and then you multiply um down and across So 3 *

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